Question 57: Laws of Motion

Question

A body of weight $$200 \mathrm{~N}$$ is suspended from a tree branch through a chain of mass $$10 \mathrm{~kg}$$. The branch pulls the chain by a force equal to (if $$\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$$) :

Accepted Answer

To determine the force that the branch pulls on the chain, we need to consider the combined weight of the body and the chain, as this is the total force that the branch must support due to gravity.
The weight of the body is given as $$200\, \mathrm{N}$$.
To find the weight of the chain, we use the formula for weight, which is the mass of an object multiplied by the acceleration due to gravity ($$g$$). The mass of the chain is given as $$10\, \mathrm{kg}$$ and $$g = 10\, \mathrm{m/s}^2$$, so:
$$	ext{Weight of the chain} = 	ext{Mass of the chain} 	imes g$$
$$= 10\, \mathrm{kg} 	imes 10\, \mathrm{m/s}^2$$
$$= 100\, \mathrm{N}$$
The total force that the branch must support is the sum of the weight of the body and the weight of the chain:
$$	ext{Total force} = 	ext{Weight of the body} + 	ext{Weight of the chain}$$
$$= 200\, \mathrm{N} + 100\, \mathrm{N}$$
$$= 300\, \mathrm{N}$$
Therefore, the branch pulls the chain by a force of $$300\, \mathrm{N}$$, which corresponds to Option A.

Answer

300 N

Answer

100 N

Answer

150 N

Answer

200 N

Laws of Motion

A body of weight $200 \mathrm{~N} is suspended from a tree branch through a chain of mass 10 \mathrm{~kg}. The branch pulls the chain by a force equal to (if \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$) :

Choose the correct answer: