Question 211: Laws of Motion

Question

A horizontal force $$10 \mathrm{~N}$$ is applied to a block $$A$$ as shown in figure. The mass of blocks $$A$$ and $$B$$ are $$2 \mathrm{~kg}$$ and 3 $$\mathrm{kg}$$ respectively. The blocks slide over a frictionless surface. The force exerted by block $$A$$ on block $$B$$ is :

Accepted Answer

$$
\begin{aligned}
& F=\left(M_1+M_2ight) a \
& a=\frac{10}{2+3}=2 \mathrm{~ms}^{-2} \
& F^{\prime}=M_2(2)=3 	imes 2 \mathrm{~N}=6 \mathrm{~N}
\end{aligned}
$$

Answer

Zero

Answer

4 N

Answer

6 N

Answer

10 N

Laws of Motion

A horizontal force $10 \mathrm{~N} is applied to a block A as shown in figure. The mass of blocks A and B are 2 \mathrm{~kg} and 3 \mathrm{kg} respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B$ is :

Choose the correct answer: