Back to Laws of Motion
Class 11PhysicsChapter-4

Laws of Motion

Question 123 of 262

123MediumJEE Mains2020

A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid point of the rope such that the top half of the rope makes an angle of 45o with the vertical. Then F equal : (Take g = 10 ms–2 and the rope to be massless)

Choose the correct answer: