Question 169: Units , Dimensions and Error Analysis

Question

Dimensional formula for thermal conductivity is (here K denotes the temperature):

Accepted Answer

$$ 	herefore $$ $${{d	heta } \over {dt}} = kA{{dT} \over {dx}}$$
$$ \Rightarrow $$ k = $${{\left( {{{d	heta } \over {dt}}} ight)} \over {A\left( {{{dT} \over {dx}}} ight)}}$$
$$ \Rightarrow $$ [k] = $${{\left[ {M{L^2}{T^{ - 3}}} ight]} \over {\left[ {{L^2}} ight]\left[ {K{L^{ - 1}}} ight]}}$$
= [MLT
Ã¢ÂÂ3
K
Ã¢ÂÂ1
]

Answer

MLT–3K–1

Answer

MLT–2K–2

Answer

MLT–2K

Answer

MLT–3K

Units , Dimensions and Error Analysis

Dimensional formula for thermal conductivity is (here K denotes the temperature):

Choose the correct answer: