Question 168: Units , Dimensions and Error Analysis

Question

A quantity x is given by $$\left( {{{IF{v^2}} \over {W{L^4}}}} \right)$$ in terms of moment of inertia I, force F, velocity v, work W and
Length L. The dimensional formula for x is same as that of :

Accepted Answer

x = $$\left( {{{IF{v^2}} \over {W{L^4}}}} ight)$$
$$ 	herefore $$ [x] = $${{\left[ {M{L^2}} ight]\left[ {ML{T^{ - 2}}} ight]{{\left[ {L{T^{ - 1}}} ight]}^2}} \over {\left[ {M{L^2}{T^{ - 2}}} ight]{{\left[ L ight]}^4}}}$$
= [ML
-1
T
-2
]
= [Energy density]

Answer

Coefficient of viscosity

Answer

Force constant

Answer

Energy density

Answer

Planck's constant

Units , Dimensions and Error Analysis

A quantity x is given by $\left( {{{IF{v^2}} \over {W{L^4}}}} \right)$ in terms of moment of inertia I, force F, velocity v, work W and Length L. The dimensional formula for x is same as that of :

Choose the correct answer: