Question 680: Centre of Mass and Rotational Motion

Question

A tube of length L is filled completely with an incompressible liquid of mass M and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with  a uniform angular velocity $$\omega $$. The force exerted by the liquid at the other end  is

Accepted Answer

The centre of the tube will be at length
L/2. So radius r = L/2.
The force exerted by the liquid at the other end
= centrifugal force
Centrifugal force
= $$Mr{\omega ^2} = M\left( {{L \over 2}} \right){\omega ^2} = {{ML{\omega ^2}} \over 2}$$

Answer

$${{M{L^2}{\omega ^2}} \over 2}$$

Answer

$${{ML{\omega ^2}} \over 2}$$

Answer

$${{M{L^2}\omega } \over 2}$$

Answer

$$ML{\omega ^2}$$

Centre of Mass and Rotational Motion

A tube of length L is filled completely with an incompressible liquid of mass M and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity $\omega $. The force exerted by the liquid at the other end is

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