Question 681: Centre of Mass and Rotational Motion

Question

The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc

Accepted Answer

Moment of inertia of a uniform circular
disc about an axis through its centre and
perpendicular to its plane is $${I_C} = {1 \over 2}M{R^2}$$ by the theorem of parallel axes.
$$ 	herefore $$ Moment of inertia of a uniform circular disc
about an axis touching the disc at its diameter and
normal to the disc is I.
$$I = {I_C} + M{h^2} = {1 \over 2}M{R^2} + M{R^2} = {3 \over 2}M{R^2}$$

Answer

$${1 \over 2}$$MR2

Answer

MR2

Answer

$${2 \over 5}M{R^2}$$

Answer

$${3 \over 2}M{R^2}$$

Centre of Mass and Rotational Motion

The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc

Choose the correct answer: