Question 353: Gravitation

Question

The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite will satellite is increased to four times the previous value, the new time period of the satellite will be

Accepted Answer

$$\begin{aligned}
& \mathrm{T}^2 \alpha \mathrm{r}^3 \
& 	herefore \frac{\mathrm{T}_2^2}{\mathrm{~T}_1^2}=\frac{\mathrm{r}_2^3}{\mathrm{r}_1^3}=(4)^3=64
\end{aligned}$$
$$	herefore \frac{\mathrm{T}_2}{\mathrm{~T}_1}=8$$
or $$\mathrm{T}_2=8 \mathrm{~T}_1=8 	imes 5=40$$ hours.

Answer

20 hours

Answer

40 hours

Answer

80 hours

Answer

10 hours

Gravitation

The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite will satellite is increased to four times the previous value, the new time period of the satellite will be

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