Question 352: Gravitation

Question

The period of revolution of planet $$\mathrm{A}$$ around the sun is 8 times that of planet $$\mathrm{B}$$. How many times the distance of A from the sun is greater than that of B from the sun?

Accepted Answer

$$\begin{aligned}
& \left(\frac{R_1}{R_2}ight)^3=\left(\frac{T_1}{T_2}ight)^2=(8)^2=64 \\
	herefore & \frac{R_1}{R_2}=(64)^{\frac{1}{3}}=4 \\
	herefore & R_1=4 R_2 \\
	herefore & R_1-R_2=4 R_2-R_2=3 R_2
\end{aligned}$$

Answer

5 times

Answer

2 times

Answer

3 times

Answer

6 times

Gravitation

The period of revolution of planet $\mathrm{A} around the sun is 8 times that of planet \mathrm{B}$. How many times the distance of A from the sun is greater than that of B from the sun?

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