Question 301: Thermodynamics & KTG

Question

Match List I with List II

List I

List II

A.
Isothermal Process
I.
Work done by the gas decreases internal energy

B.
Adiabatic Process
II.
No change in internal energy

C.
Isochoric Process
III.
The heat absorbed goes partly to increase internal energy and partly to do work

D.
Isobaric Process
IV.
No work is done on or by the gas

Choose the correct answer from the options given below :

Accepted Answer

$$
\Delta \mathrm{U}=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T}
$$
For isothermal process $\mathrm{T}$ is constant
So $\Delta \mathrm{U}=0$
$\mathrm{A} \longrightarrow \mathrm{II}$
Adiabatic process
$$
\begin{aligned}
& \Delta \mathrm{Q}=0 \\
& \Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{W} \\
& \Delta \mathrm{U}=-\Delta \mathrm{W}
\end{aligned}
$$
Work done by gas is positive
So $\Delta \mathrm{U}$ is negative
$$
	ext { B } \longrightarrow 	ext { I }
$$
For Isochoric process $\Delta \mathrm{W}=0$
$$
\mathrm{C} \longrightarrow \mathrm{IV}
$$
For Isobaric process
$$
\begin{aligned}
& \Delta \mathrm{W}=\mathrm{P} \Delta \mathrm{V} 
eq 0 \\
& \Delta \mathrm{U}=\mathrm{nC}_{\mathrm{V}} \Delta \mathrm{T} 
eq 0
\end{aligned}
$$
Heat absorbed goes partly to increase internal energy and partly to do work.

Answer

A-I, B-II, C-IV, D-III

Answer

A-II, B-I, C-III, D-IV

Answer

A-II, B-I, C-IV, D-III

Answer

A-I, B-II, C-III, D-IV

Thermodynamics & KTG

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