Question 302: Thermodynamics & KTG

Question

The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by :-

Accepted Answer

$$
\begin{aligned}
& \frac{	ext { reading on scale }-	ext { Lower fixed point }}{	ext { upper fixed point-lower fixed point }}=	ext { constant } \\
& \frac{t_P-30}{180-30}=\frac{t_Q-0}{100-0} \\
& \frac{t_P-30}{150}=\frac{t_Q}{100}
\end{aligned}
$$

Answer

$${{{t_P}} \over {100}} = {{{t_Q} - 180} \over {150}}$$

Answer

$${{{t_P}} \over {180}} - {{{t_Q} - 40} \over {100}}$$

Answer

$${{{t_Q}} \over {150}} = {{{t_P} - 180} \over {100}}$$

Answer

$${{{t_Q}} \over {100}} = {{{t_P} - 30} \over {150}}$$

Thermodynamics & KTG

The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by :-

Choose the correct answer: