Question 881: Thermodynamics & KTG

Question

For a gas having '$$\mathrm{X}$$' degrees of freedom, '$$\gamma$$' is ($$\gamma=$$ ratio of specific heats $$=\mathrm{C_P / C_V}$$)

Accepted Answer

$$\gamma$$ and degrees of freedom is related by
$$\gamma=\frac{\mathrm{f}+2}{\mathrm{f}}$$
Where $$f$$ is the number of degrees of freedoms.
Given $$\mathrm{f}=\mathrm{X}$$,
$$	herefore \quad \gamma=\frac{X+2}{X}=1+\frac{2}{X}$$

Answer

$$\frac{1+X}{2}$$

Answer

$$1+\frac{X}{2}$$

Answer

$$1+\frac{2}{x}$$

Answer

$$1+\frac{1}{x}$$

Thermodynamics & KTG

For a gas having '$\mathrm{X}' degrees of freedom, '\gamma' is (\gamma= ratio of specific heats =\mathrm{C_P / C_V}$)

Choose the correct answer: