Question 946: Thermodynamics & KTG

Question

A perfectly black body emits a radiation at temperature 'T$$_1$$' K. If it is to radiate at 16 times this power, its temperature 'T$$_2$$' K should be

Accepted Answer

$${{{P_2}} \over {{P_1}}} = {\left( {{{{T_2}} \over {{T_1}}}} ight)^4}$$
$$	herefore$$ $$16 = {\left( {{{{T_2}} \over {{T_1}}}} ight)^4}$$
$$	herefore$$ $${{{T_2}} \over {{T_1}}} = 2$$

Answer

8T$$_1$$

Answer

4T$$_1$$

Answer

2T$$_1$$

Answer

16T$$_1$$

Thermodynamics & KTG

A perfectly black body emits a radiation at temperature 'T$_1' K. If it is to radiate at 16 times this power, its temperature 'T_2$' K should be

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