Question 945: Thermodynamics & KTG

Question

Two stars 'P' and 'Q' emit yellow and blue light respectively. The relation between their temperatures $$\left(\mathrm{T}_{\mathrm{P}}\right.$$ and $$\left.\mathrm{T}_{\mathrm{Q}}\right)$$ is

Accepted Answer

According to Wien's law, $$\lambda$$T = constant
$$	herefore \mathrm{T \propto \frac{1}{\lambda}}$$
Wavelength of blue light is less than that of yellow light. Hence, temperature of Q is greater than temperature of P.

Answer

$$\mathrm{T_P=T_Q}$$

Answer

$$\mathrm{T}_{\mathrm{P}}=\frac{\mathrm{T}_{\mathrm{Q}}}{2}$$

Answer

$$\mathrm{T}_{\mathrm{P}}>\mathrm{T}_{\mathrm{Q}}$$

Answer

$$\mathrm{T}_{\mathrm{P}}<\mathrm{T}_{\mathrm{Q}}$$

Thermodynamics & KTG

Two stars 'P' and 'Q' emit yellow and blue light respectively. The relation between their temperatures $\left(\mathrm{T}_{\mathrm{P}}\right. and \left.\mathrm{T}_{\mathrm{Q}}\right)$ is

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