Question 380: Waves Optics

Question

In Young's double slit experiment, the '$$\mathrm{n^{th}}$$' maximum of wavelength '$$\lambda_1$$' is at a distance '$$\mathrm{y_1}$$' from the central maximum. When the wavelength of the source is changed to '$$\lambda_2$$', $$\left(\frac{\mathrm{n}}{2}ight)^{	ext {th }}$$ maximum is at a distance of '$$\mathrm{y_2}$$' from its central maximum. The ratio $$\frac{y_1}{y_2}$$ is

Accepted Answer

$$\begin{aligned} & Y_1=\frac{\mathrm{n} \lambda_1 D}{\mathrm{~d}}, \quad Y_2=\frac{\mathrm{n} \lambda_2 \mathrm{D}}{\mathrm{d}} \ & 	herefore \frac{\mathrm{Y}_1}{\mathrm{Y}_2}=\frac{2 \lambda_1}{\lambda_2}\end{aligned}$$

Answer

$$\frac{\lambda_2}{2 \lambda_1}$$

Answer

$$\frac{2 \lambda_1}{\lambda_2}$$

Answer

$$\frac{2 \lambda_2}{\lambda_1}$$

Answer

$$\frac{\lambda_1}{2 \lambda_2}$$

Waves Optics

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