Question 381: Waves Optics

Question

Light of wavelength '$$\lambda$$' is incident on a single slit of width 'a' and the distance between slit and screen is 'D'. In diffraction pattern, if slit width is equal to the width of the central maximum then $$\mathrm{D}=$$

Accepted Answer

Width of central maximum $$=\frac{2\lambda D}{a}$$
$$	herefore a=\frac{2\lambda D}{a}$$
$$	herefore D=\frac{a^2}{2\lambda}$$

Answer

$$\frac{a^2}{\lambda}$$

Answer

$$\frac{\mathrm{a}}{\lambda}$$

Answer

$$\frac{a^2}{2 \lambda}$$

Answer

$$\frac{\mathrm{a}}{2 \lambda}$$

Waves Optics

Light of wavelength '$\lambda' is incident on a single slit of width 'a' and the distance between slit and screen is 'D'. In diffraction pattern, if slit width is equal to the width of the central maximum then \mathrm{D}=

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