Question 554: Atoms & Nuclei

Question

The decay constant of a radio isotope is $$\lambda $$. If A
1
and A
2
are its activities at times t
1
and t
2
respectively, the number of nuclei which have decayed during the time (t
1
$$-$$ t
2
)

Accepted Answer

A
1
= $$\lambda $$N
1
at time t
1
A
2
= $$\lambda $$N
2
at time t
2
Therefore, number of nuclei decayed during time
interval (t
1
Ã¢ÂÂ t
2
) is
N
1
- N
2
= $${{\left[ {{A_1} - {A_2}} \right]} \over \lambda }$$

Answer

A
1
t
1
$$-$$ A
2
t
2

Answer

A
1
$$-$$ A
2

Answer

(A
1
$$-$$ A
2
)/$$\lambda $$

Answer

$$\lambda ({A_1} - {A_2})$$

Atoms & Nuclei

The decay constant of a radio isotope is $\lambda . If A 1 and A 2 are its activities at times t 1 and t 2 respectively, the number of nuclei which have decayed during the time (t 1 -$ t 2 )

Choose the correct answer: