Question 553: Atoms & Nuclei

Question

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is

Accepted Answer

1
H
2
+
1
H
2
$$ 	o $$
2
He
4
+ $$\Delta $$E
The binding energy per nucleon of a deuteron = 1.1 MeV
$$ 	herefore $$ Total binding energy = 2 ÃÂ 1.1 = 2.2 MeV
The binding energy per nucleon of a helium nuclei
= 7 MeV
$$ 	herefore $$ Total binding energy = 4 ÃÂ 7 = 28 MeV
Hence, energy released
$$\Delta $$E = (28 Ã¢ÂÂ 2 ÃÂ 2.2) = 23.6 MeV

Answer

23.6 MeV

Answer

2.2 MeV

Answer

28.0 MeV

Answer

30.2 MeV

Atoms & Nuclei

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is

Choose the correct answer: