Question 301: Atoms & Nuclei

Question

When a $${U^{238}}$$ nucleus originally at rest, decays by emitting an alpha particle having a speed $$'u',$$ the recoil speed of the residual nucleus is

Accepted Answer

Here, conservation of linear momentum can be applied
$$238 	imes 0 = 4u + 234v $$
$$	herefore$$ $$v =  - {4 \over {234}}u$$
$$	herefore$$ speed $$ = |\overrightarrow v | = {4 \over {234}}u$$

Answer

$${{4\mu } \over {238}}$$

Answer

$$ - {{4\mu } \over {234}}$$

Answer

$$  {{4\mu } \over {234}}$$

Answer

$$ - {{4\mu } \over {238}}$$

Atoms & Nuclei

When a ${U^{238}} nucleus originally at rest, decays by emitting an alpha particle having a speed 'u',$ the recoil speed of the residual nucleus is

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