Question 300: Atoms & Nuclei

Question

A nucleus with $$Z=92$$ emits the following in a sequence: 
$$$\alpha ,{\beta ^ - },{\beta ^ - },\alpha ,\alpha ,\alpha ,\alpha ,\alpha ,{\beta ^ - },{\beta ^ - },\alpha ,{\beta ^ + },{\beta ^ + },\alpha $$$
Then $$Z$$ of the resulting nucleus is

Accepted Answer

The number of $$\alpha $$ - particles released $$=8$$
Therefore the atomic number should decrease by $$16$$
The number of $${\beta ^ - }$$ - particles released $$=4$$
Therefore the atomic number should increase by $$4.$$
Also the number of $${\beta ^ + }$$ particles released is $$2,$$ which
should decrease the atomic number by $$2.$$
Therefore the final atomic number is
$$92-16+4-2=78$$

Answer

$$76$$

Answer

$$78$$

Answer

$$82$$

Answer

$$74$$

Atoms & Nuclei

A nucleus with $Z=92 emits the following in a sequence: \alpha ,{\beta ^ - },{\beta ^ - },\alpha ,\alpha ,\alpha ,\alpha ,\alpha ,{\beta ^ - },{\beta ^ - },\alpha ,{\beta ^ + },{\beta ^ + },\alpha Then Z$ of the resulting nucleus is

Choose the correct answer: