Question 592: Electrostatics & Capacitance

Question

A square loop of sides $a=1 \mathrm{~m}$ is held normally in front of a point charge $\mathrm{q}=1 \mathrm{C}$ at a distance $\frac{\mathrm{a}}{2}$. The flux of the electric field through the shaded region is $\frac{5}{\mathrm{p}} 	imes \frac{1}{\varepsilon_0} \frac{\mathrm{Nm}^2}{\mathrm{C}}$, where the value of p is ________ .

Accepted Answer

Total flux through square $=\frac{\mathrm{q}}{\epsilon_0}\left(\frac{1}{6}ight)$
Lets divide square is 8 equal parts.
Flux is same for each part.
$	herefore$ Flux through shaded portion is $\frac{5}{8}$ (Total flux)
$$ =\frac{5}{8} 	imes \frac{\mathrm{q}}{\epsilon_0} \frac{1}{6}=\frac{5}{48} \frac{1}{\epsilon_0} $$
$	herefore$ Required Ans. is 48

Electrostatics & Capacitance

Integer / Numeric Answer Type