Question 13: Semiconductors and Logic Gates

Question

$ 	ext { Identify the correct truth table of the given logic circuit. } $
![](https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ml99shkf/37d23c22-e81a-4282-bbe8-e74d86a47160/4ac9f7f0-0277-11f1-bf92-8d689bc79bfa/file-6y3zli1ml99shkg.png?format=png)

Accepted Answer

Logic gate 1 is an AND gate with both inputs shorted together to $A$. So, the output $\$
$\left(Y_1ight)$ is just $A$. $\$
$ \begin{array}{|c|c|c|} \hline A & B & Y_1 \ \hline 0 & 0 & 0 \ \hline 0 & 1 & 0 \ \hline 1 & 0 & 1 \ \hline 1 & 1 & 1 \ \hline \end{array} $ $\$
Logic Gate 2 is an NAND gate with inputs A and B and its output is $\mathrm{Y}_2$. $\$
$ \begin{array}{|c|c|c|c|} \hline A & B & A \cdot B & Y_2=\overline{A \cdot B} \ \hline 0 & 0 & 0 & 1 \ \hline 0 & 1 & 0 & 1 \ \hline 1 & 0 & 0 & 1 \ \hline 1 & 1 & 1 & 0 \ \hline \end{array} $ $\$
Logic gate 3 is an AND gate with both inputs shorted to the output of the logic gate 2. So, the output ( $Y_3$ ) is just the output of logic gate 2. $\$
$ \begin{array}{|c|c|c|c|c|} \hline A & B & A \cdot B & Y_2=\overline{A \cdot B} & Y_3 \ \hline 0 & 0 & 0 & 1 & 1 \ \hline 0 & 1 & 0 & 1 & 1 \ \hline 1 & 0 & 0 & 1 & 1 \ \hline 1 & 1 & 1 & 0 & 0 \ \hline \end{array} $ $\$
Logic gate 4 is an AND gate that takes the output from the outputs $(\mathrm{Y})$ of logic gate 1 and the logic gate 3. $\$
$ \begin{array}{|c|c|c|c|c|} \hline A & B & Y_1 & Y_3 & Y=Y_1 \cdot Y_3 \ \hline 0 & 0 & 0 & 1 & 0 \ \hline 0 & 1 & 0 & 1 & 0 \ \hline 1 & 0 & 1 & 1 & 1 \ \hline 1 & 1 & 1 & 0 & 0 \ \hline \end{array} $ $\$
Therefore, the truth table of the given logic gate is, $\$
$ \begin{aligned} &\begin{array}{|c|c|c|} \hline A & B & Y \ \hline 0 & 0 & 0 \ \hline 0 & 1 & 0 \ \hline 1 & 0 & 1 \ \hline 1 & 1 & 0 \ \hline \end{array}\ &	ext { Hence, the correct option is (A) } \end{aligned} $
![](https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1mljaj3e2/f7490ec6-f9df-4a8e-a035-5813e5753f20/052dc4a0-07fa-11f1-a513-671ec3d625a9/file-6y3zli1mljaj3e3.png?format=png)

Answer

$ \begin{array}{|c|c|c|} \hline 	ext { A } & 	ext { B } & 	ext { Y } \ \hline \hline 0 & 0 & 0 \ \hline \hline 0 & 1 & 0 \ \hline 1 & 0 & 1 \ \hline 1 & 1 & 0 \ \hline \end{array} $

Answer

$ \begin{array}{|c|c|c|} \hline 	ext { A } & 	ext { B } & 	ext { Y } \ \hline \hline 0 & 0 & 0 \ \hline \hline 0 & 1 & 1 \ \hline 1 & 0 & 1 \ \hline 1 & 1 & 0 \ \hline \end{array} $

Answer

$ \begin{array}{|c|c|c|} \hline 	ext { A } & 	ext { B } & 	ext { Y } \ \hline \hline 0 & 0 & 1 \ \hline \hline 0 & 1 & 1 \ \hline \hline 1 & 0 & 1 \ \hline \hline 1 & 1 & 0 \ \hline \end{array} $

Answer

$ \begin{array}{|c|c|c|} \hline 	ext { A } & 	ext { B } & 	ext { Y } \ \hline \hline 0 & 0 & 1 \ \hline \hline 0 & 1 & 0 \ \hline 1 & 0 & 1 \ \hline 1 & 1 & 0 \ \hline \end{array} $

Semiconductors and Logic Gates

\text{ Identify the correct truth table of the given logic circuit. }

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