Question 29: Semiconductors and Logic Gates

Question

The truth table for the circuit given below is:

Accepted Answer

A
B
$$\overline A $$
$$\overline B $$
$$A.\overline B $$
$$\overline A .B$$
$\mathrm{Y=A.\bar{B}+\bar{A} . B}$
0
0
1
1
0
0
0
0
1
1
0
0
1
1
1
0
0
1
1
0
1
1
1
0
0
0
0
0
Hence, option 4 is correct.

Answer

A
B
Y
0
0
0
1
1
1
1
0
1
0
1
1

Answer

A
B
Y
0
0
0
1
0
1
0
1
0
1
1
0

Answer

A
B
Y
0
0
0
1
0
0
1
1
0
0
1
1

Answer

A
B
Y
0
0
0
0
1
1
1
0
1
1
1
0

Semiconductors and Logic Gates

The truth table for the circuit given below is:

Choose the correct answer: