Question 149: Semiconductors and Logic Gates

Question

The reverse breakdown voltage of a Zener
diode is 5.6 V in the given circuit.
The current IZ through the Zener is :

Accepted Answer

9 = Vz + V
R
1
V
Z
= 5.6 V
V
R
1
= 9 - 5.6
V
R
1
=  3.4
$${I_{{R_1}}} = {{{V_{{R_1}}}} \over R} = {{3.4} \over {200}};\,{I_{{R_1}}} = 17\,mA$$
V
z
= V
R
2
=  I
R
2
(R
2
)
$${{5.6} \over {700}} = {I_{{R_2}}}$$;     $${I_{{R_2}}} = 7\,mA$$
I
z
= (17 Ã¢ÂÂ 7) mA = 10 mA

Answer

7 mA

Answer

17 mA

Answer

15mA

Answer

10 mA

Semiconductors and Logic Gates

The reverse breakdown voltage of a Zener diode is 5.6 V in the given circuit. The current IZ through the Zener is :

Choose the correct answer: