Question 116: Semiconductors and Logic Gates

Question

The following logic gate is equivalent to :

Accepted Answer

Output of first NAND gate with input A
$$\eqalign{
  &  = \overline {A.A}   \cr 
  &  = \overline A  + \overline A   \cr 
  &  = \overline A  \cr} $$
Similarly, Output of first NAND gate with input B
$$ = \overline B $$
$$\eqalign{
  & {Y_1} = \overline {\overline A .\overline B }   \cr 
  &  = \overline {\overline A }  + \overline {\overline B }   \cr 
  &  = A + B \cr} $$
$$\eqalign{
  & Y = \overline {\left( {A + B} \right).\left( {A + B} \right)}   \cr 
  &  = \overline {\left( {A + B} \right)}  + \overline {\left( {A + B} \right)}   \cr 
  &  = \overline {\left( {A + B} \right)}  \cr} $$
So, given logic gates circuit is a NOR gate.

Answer

NOR Gate

Answer

NAND Gate

Answer

OR Gate

Answer

AND Gate

Semiconductors and Logic Gates

The following logic gate is equivalent to :

Choose the correct answer: