Question 64: Semiconductors and Logic Gates

Question

The logic performed by the circuit shown in figure is equivalent to :

Accepted Answer

$$
Y=\overline{\bar{a}+\overline{\mathrm{b}}}=a \cdot b
$$
The truth table for the given circuit will be
$$
\begin{array}{|c|c|c|}
\hline \mathrm{a} & \mathrm{b} & 	ext { output } \
\hline 0 & 0 & 0 \
\hline 0 & 1 & 0 \
\hline 1 & 0 & 0 \
\hline 1 & 1 & 1 \
\hline
\end{array}
$$
Hence it will be equivalent to
AND
gate.

Answer

NAND

Answer

AND

Answer

OR

Answer

NOR

Semiconductors and Logic Gates

The logic performed by the circuit shown in figure is equivalent to :

Choose the correct answer: