Question 470: Thermodynamics & KTG

Question

Two moles of helium gas are taken over the cycle $$ABCD$$, as shown in the $$P$$-$$T$$ diagram.
The net work done on the gas in the cycle $$ABCDA$$ is:

Accepted Answer

The net work in the cycle $$ABCD$$ is
$$W = {W_{AB}} + {W_{BC}} + {W_{CD}} + {W_{DA}}$$
$$ = 400R + 2.303nRT\log {{{P_B}} \over {{P_C}}} + \left( { - 400R} ight) - 414R$$
$$ = 2.303 	imes 2R 	imes 500\log {{2 	imes {{10}^5}} \over {1 	imes {{10}^5}}} - 414R$$
$$ = 693.2\,R - 414\,R = 279.2\,R$$

Answer

$$276$$ $$R$$

Answer

$$1076$$ $$R$$

Answer

$$1904$$ $$R$$

Answer

zero

Thermodynamics & KTG

Two moles of helium gas are taken over the cycle $ABCD, as shown in the P-T diagram. The net work done on the gas in the cycle ABCDA$ is:

Choose the correct answer: