Question 469: Thermodynamics & KTG

Question

Two moles of helium gas are taken over the cycle $$ABCD,$$ as shown in the $$P$$-$$T$$ diagram.
The work done on the gas in taking it from $$D$$ to $$A$$ is :

Accepted Answer

Work done by the system in the isothermal process
$$DA$$ is $$W = 2.303nRT\,{\log _{10}}{{{P_D}} \over {{P_A}}}$$
$$ = 2.303 	imes 2R 	imes 300{\log _{10}}{{1 	imes {{10}^5}} \over {2 	imes {{10}^5}}} =  - 414R.$$
Therefore work done on the gas is $$ + \,414\,R.$$

Answer

$$+414$$ $$R$$

Answer

$$-690$$ $$R$$

Answer

$$+690$$ $$R$$

Answer

$$-414$$ $$R$$

Thermodynamics & KTG

Two moles of helium gas are taken over the cycle $ABCD, as shown in the P-T diagram. The work done on the gas in taking it from D to A$ is :

Choose the correct answer: