Question 929: Thermodynamics & KTG

Question

The mean free path for a gas, with molecular diameter d and number density n can be expressed as :

Accepted Answer

As per the formula,
$$\lambda  = {1 \over {\sqrt 2 n\pi {d^2}}}$$

Answer

$${1 \over {\sqrt 2 n\pi {d^2}}}$$

Answer

$${1 \over {\sqrt 2 {n^2}\pi {d^2}}}$$

Answer

$${1 \over {\sqrt 2 {n^2}{\pi ^2}{d^2}}}$$

Answer

$${1 \over {\sqrt 2 n\pi d}}$$

Thermodynamics & KTG