Question 928: Thermodynamics & KTG

Question

The average thermal energy for a mono-atomic gas is : (k
B
is Boltzmann constant and T absolute temperature)

Accepted Answer

The degree of freedom for monoatomic gas is 3. So, average thermal energy per molecule,
K.E.
avg
= $${3 \over 2}{k_B}T$$

Answer

$${3 \over 2}{k_B}T$$

Answer

$${5 \over 2}{k_B}T$$

Answer

$${7 \over 2}{k_B}T$$

Answer

$${1 \over 2}{k_B}T$$

Thermodynamics & KTG